3+11/2h=35/4h

Solution for 3+11/2h=35/4h equation:

3+11/2h=35/4h

We move all terms to the left:

3+11/2h-(35/4h)=0


Domain of the equation: 2h!=0

h!=0/2

h!=0

h∈R



Domain of the equation: 4h)!=0

h!=0/1

h!=0

h∈R


We add all the numbers together, and all the variables

11/2h-(+35/4h)+3=0

We get rid of parentheses

11/2h-35/4h+3=0

We calculate fractions


44h/8h^2+(-70h)/8h^2+3=0

We multiply all the terms by the denominator


44h+(-70h)+3*8h^2=0

Wy multiply elements

24h^2+44h+(-70h)=0

We get rid of parentheses

24h^2+44h-70h=0

We add all the numbers together, and all the variables

24h^2-26h=0

a = 24; b = -26; c = 0;
Δ = b2-4ac
Δ = -262-4·24·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-26}{2*24}=\frac{0}{48}
=0
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+26}{2*24}=\frac{52}{48}
=1+1/12
$