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3+10x^2=4x+2
We move all terms to the left:
3+10x^2-(4x+2)=0
We get rid of parentheses
10x^2-4x-2+3=0
We add all the numbers together, and all the variables
10x^2-4x+1=0
a = 10; b = -4; c = +1;
Δ = b2-4ac
Δ = -42-4·10·1
Δ = -24
Delta is less than zero, so there is no solution for the equation
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