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3+1/9x=1/5x
We move all terms to the left:
3+1/9x-(1/5x)=0
Domain of the equation: 9x!=0
x!=0/9
x!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/9x-(+1/5x)+3=0
We get rid of parentheses
1/9x-1/5x+3=0
We calculate fractions
5x/45x^2+(-9x)/45x^2+3=0
We multiply all the terms by the denominator
5x+(-9x)+3*45x^2=0
Wy multiply elements
135x^2+5x+(-9x)=0
We get rid of parentheses
135x^2+5x-9x=0
We add all the numbers together, and all the variables
135x^2-4x=0
a = 135; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·135·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*135}=\frac{0}{270} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*135}=\frac{8}{270} =4/135 $
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