3+(z/4)+5=19

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Solution for 3+(z/4)+5=19 equation: 



3+(z/4)+5=19

We move all terms to the left:

3+(z/4)+5-(19)=0

We add all the numbers together, and all the variables

(+z/4)+3+5-19=0

We add all the numbers together, and all the variables

(+z/4)-11=0

We get rid of parentheses

z/4-11=0

We multiply all the terms by the denominator


z-11*4=0

We add all the numbers together, and all the variables

z-44=0

We move all terms containing z to the left, all other terms to the right

z=44

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