3+(x+3)=12+(6-x)

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Solution for 3+(x+3)=12+(6-x) equation: 



3+(x+3)=12+(6-x)

We move all terms to the left:

3+(x+3)-(12+(6-x))=0

We add all the numbers together, and all the variables

(x+3)-(12+(-1x+6))+3=0

We get rid of parentheses

x-(12+(-1x+6))+3+3=0



We calculate terms in parentheses: -(12+(-1x+6)), so:

12+(-1x+6)

determiningTheFunctionDomain
(-1x+6)+12

We get rid of parentheses

-1x+6+12

We add all the numbers together, and all the variables

-1x+18

Back to the equation:

-(-1x+18)



We add all the numbers together, and all the variables

x-(-1x+18)+6=0

We get rid of parentheses

x+1x-18+6=0

We add all the numbers together, and all the variables

2x-12=0

We move all terms containing x to the left, all other terms to the right

2x=12

x=12/2

x=6

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