3+(t-12)=27

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Solution for 3+(t-12)=27 equation: 



3+(t-12)=27

We move all terms to the left:

3+(t-12)-(27)=0

We add all the numbers together, and all the variables

(t-12)-24=0

We get rid of parentheses

t-12-24=0

We add all the numbers together, and all the variables

t-36=0

We move all terms containing t to the left, all other terms to the right

t=36

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