3+(6/P)=9/p

Solution for 3+(6/P)=9/p equation:

3+(6/)=9/P

We move all terms to the left:

3+(6/)-(9/P)=0


Domain of the equation: P)!=0

P!=0/1

P!=0

P∈R


We add all the numbers together, and all the variables

-(+9/P)+3+(+6/)=0

We get rid of parentheses

-9/P+3+6/=0

We calculate fractions


()/(P*)+6P/(P*)+3=0

We add all the numbers together, and all the variables

()/(+P*)+6P/(+P*)+3=0

We multiply all the terms by the denominator


6P+3*(+P*)+()=0

We add all the numbers together, and all the variables

6P+3*(+P*)=0

We multiply parentheses

3P^2+6P=0

a = 3; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·3·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*3}=\frac{-12}{6}
=-2
$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*3}=\frac{0}{6}
=0
$