3+(5)/(x-2)=(x+1)/x

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Solution for 3+(5)/(x-2)=(x+1)/x equation: 


D( x )

x-2 = 0

x = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x = 0

x = 0

x in (-oo:0) U (0:2) U (2:+oo)

5/(x-2)+3 = (x+1)/x // - (x+1)/x

5/(x-2)-((x+1)/x)+3 = 0

5/(x-2)+(-1*(x+1))/x+3 = 0

(5*x)/(x*(x-2))+(-1*(x+1)*(x-2))/(x*(x-2))+(3*x*(x-2))/(x*(x-2)) = 0

3*x*(x-2)-1*(x+1)*(x-2)+5*x = 0

3*x^2-x^2+6*x-6*x+2 = 0

2*x^2+2 = 0

(2*x^2+2)/(x*(x-2)) = 0

(2*x^2+2)/(x*(x-2)) = 0 // * x*(x-2)

2*x^2+2 = 0

2*x^2 = -2 // : 2

x^2 = -1

x belongs to the empty set

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