3+(3x+2)=8+(1x+2)

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Solution for 3+(3x+2)=8+(1x+2) equation: 



3+(3x+2)=8+(1x+2)

We move all terms to the left:

3+(3x+2)-(8+(1x+2))=0

We add all the numbers together, and all the variables

(3x+2)-(8+(x+2))+3=0

We get rid of parentheses

3x-(8+(x+2))+2+3=0



We calculate terms in parentheses: -(8+(x+2)), so:

8+(x+2)

determiningTheFunctionDomain
(x+2)+8

We get rid of parentheses

x+2+8

We add all the numbers together, and all the variables

x+10

Back to the equation:

-(x+10)



We add all the numbers together, and all the variables

3x-(x+10)+5=0

We get rid of parentheses

3x-x-10+5=0

We add all the numbers together, and all the variables

2x-5=0

We move all terms containing x to the left, all other terms to the right

2x=5

x=5/2

x=2+1/2

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