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3+(3x)/(110-x)+(3x)/(110-x)=(203)/(x)
We move all terms to the left:
3+(3x)/(110-x)+(3x)/(110-x)-((203)/(x))=0
Domain of the equation: (110-x)!=0
We move all terms containing x to the left, all other terms to the right
-x!=-110
x!=-110/-1
x!=+110
x∈R
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3x/(-1x+110)+3x/(-1x+110)-(+203/x)+3=0
We get rid of parentheses
3x/(-1x+110)+3x/(-1x+110)-203/x+3=0
We calculate fractions
(3x^2+3x)/(-1x^2+110x)+(203x-22330)/(-1x^2+110x)+3=0
We multiply all the terms by the denominator
3*(-1x^2+110x)+(3x^2+3x)+(203x-22330)=0
We multiply parentheses
-3x^2+330x+(3x^2+3x)+(203x-22330)=0
We get rid of parentheses
-3x^2+3x^2+330x+3x+203x-22330=0
We add all the numbers together, and all the variables
536x-22330=0
We move all terms containing x to the left, all other terms to the right
536x=22330
x=22330/536
x=41+177/268
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