3+(1/3+c)=134

Solution for 3+(1/3+c)=134 equation:

3+(1/3+c)=134

We move all terms to the left:

3+(1/3+c)-(134)=0


Domain of the equation: 3+c)!=0

We move all terms containing c to the left, all other terms to the right

c)!=-3

c!=-3/1

c!=-3

c∈R


We add all the numbers together, and all the variables

(+c+1/3)+3-134=0

We add all the numbers together, and all the variables

(+c+1/3)-131=0

We get rid of parentheses

c-131+1/3=0

We multiply all the terms by the denominator


c*3+1-131*3=0

We add all the numbers together, and all the variables

c*3-392=0

Wy multiply elements

3c-392=0

We move all terms containing c to the left, all other terms to the right

3c=392

c=392/3

c=130+2/3