3*sin(x)=1+cos(2x)

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Solution for 3*sin(x)=1+cos(2x) equation:


Simplifying
3sin(x) = 1 + cos(2x)

Multiply ins * x
3insx = 1 + cos(2x)

Remove parenthesis around (2x)
3insx = 1 + cos * 2x

Reorder the terms for easier multiplication:
3insx = 1 + 2cos * x

Multiply cos * x
3insx = 1 + 2cosx

Solving
3insx = 1 + 2cosx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Divide each side by '3nsx'.
i = 0.3333333333n-1s-1x-1 + 0.6666666667cn-1o

Simplifying
i = 0.3333333333n-1s-1x-1 + 0.6666666667cn-1o

Reorder the terms:
i = 0.6666666667cn-1o + 0.3333333333n-1s-1x-1

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