3*sin(2*x)-(4*x)+1=

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Solution for 3*sin(2*x)-(4*x)+1= equation:


Simplifying
3sin(2x) + -1(4x) + 1 = 0

Remove parenthesis around (2x)
3ins * 2x + -1(4x) + 1 = 0

Reorder the terms for easier multiplication:
3 * 2ins * x + -1(4x) + 1 = 0

Multiply 3 * 2
6ins * x + -1(4x) + 1 = 0

Multiply ins * x
6insx + -1(4x) + 1 = 0

Remove parenthesis around (4x)
6insx + -1 * 4x + 1 = 0

Multiply -1 * 4
6insx + -4x + 1 = 0

Reorder the terms:
1 + 6insx + -4x = 0

Solving
1 + 6insx + -4x = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 6insx + -1 + -4x = 0 + -1

Reorder the terms:
1 + -1 + 6insx + -4x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 6insx + -4x = 0 + -1
6insx + -4x = 0 + -1

Combine like terms: 0 + -1 = -1
6insx + -4x = -1

Add '4x' to each side of the equation.
6insx + -4x + 4x = -1 + 4x

Combine like terms: -4x + 4x = 0
6insx + 0 = -1 + 4x
6insx = -1 + 4x

Divide each side by '6nsx'.
i = -0.1666666667n-1s-1x-1 + 0.6666666667n-1s-1

Simplifying
i = -0.1666666667n-1s-1x-1 + 0.6666666667n-1s-1

Reorder the terms:
i = 0.6666666667n-1s-1 + -0.1666666667n-1s-1x-1

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