3*1=72/f-5

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Solution for 3*1=72/f-5 equation: 



3*1=72/f-5

We move all terms to the left:

3*1-(72/f-5)=0



Domain of the equation: f-5)!=0

f∈R



We add all the numbers together, and all the variables

-(72/f-5)+3=0

We get rid of parentheses

-72/f+5+3=0

We multiply all the terms by the denominator


5*f+3*f-72=0

We add all the numbers together, and all the variables

8f-72=0

We move all terms containing f to the left, all other terms to the right

8f=72

f=72/8

f=9

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