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3(x-4)-6(2x-3)=12-7x
We move all terms to the left:
3(x-4)-6(2x-3)-(12-7x)=0
We add all the numbers together, and all the variables
3(x-4)-6(2x-3)-(-7x+12)=0
We multiply parentheses
3x-12x-(-7x+12)-12+18=0
We get rid of parentheses
3x-12x+7x-12-12+18=0
We add all the numbers together, and all the variables
-2x-6=0
We move all terms containing x to the left, all other terms to the right
-2x=6
x=6/-2
x=-3
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