3*(5x-9)-8*(1-x)=4x-4*(1+4x)+39

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Solution for 3*(5x-9)-8*(1-x)=4x-4*(1+4x)+39 equation: 



3(5x-9)-8(1-x)=4x-4(1+4x)+39

We move all terms to the left:

3(5x-9)-8(1-x)-(4x-4(1+4x)+39)=0

We add all the numbers together, and all the variables

3(5x-9)-8(-1x+1)-(4x-4(4x+1)+39)=0

We multiply parentheses

15x+8x-(4x-4(4x+1)+39)-27-8=0



We calculate terms in parentheses: -(4x-4(4x+1)+39), so:

4x-4(4x+1)+39

We multiply parentheses

4x-16x-4+39

We add all the numbers together, and all the variables

-12x+35

Back to the equation:

-(-12x+35)



We add all the numbers together, and all the variables

23x-(-12x+35)-35=0

We get rid of parentheses

23x+12x-35-35=0

We add all the numbers together, and all the variables

35x-70=0

We move all terms containing x to the left, all other terms to the right

35x=70

x=70/35

x=2

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