3*(4x-5)+2*(16+4x)-6*(21-8x)=9*(2x-1)

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Solution for 3*(4x-5)+2*(16+4x)-6*(21-8x)=9*(2x-1) equation: 



3(4x-5)+2(16+4x)-6(21-8x)=9(2x-1)

We move all terms to the left:

3(4x-5)+2(16+4x)-6(21-8x)-(9(2x-1))=0

We add all the numbers together, and all the variables

3(4x-5)+2(4x+16)-6(-8x+21)-(9(2x-1))=0

We multiply parentheses

12x+8x+48x-(9(2x-1))-15+32-126=0



We calculate terms in parentheses: -(9(2x-1)), so:

9(2x-1)

We multiply parentheses

18x-9

Back to the equation:

-(18x-9)



We add all the numbers together, and all the variables

68x-(18x-9)-109=0

We get rid of parentheses

68x-18x+9-109=0

We add all the numbers together, and all the variables

50x-100=0

We move all terms containing x to the left, all other terms to the right

50x=100

x=100/50

x=2

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