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3(4x-1)=4(2x+3)
We move all terms to the left:
3(4x-1)-(4(2x+3))=0
We multiply parentheses
12x-(4(2x+3))-3=0
We calculate terms in parentheses: -(4(2x+3)), so:We get rid of parentheses
4(2x+3)
We multiply parentheses
8x+12
Back to the equation:
-(8x+12)
12x-8x-12-3=0
We add all the numbers together, and all the variables
4x-15=0
We move all terms containing x to the left, all other terms to the right
4x=15
x=15/4
x=3+3/4
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