3*(2x-5)+4x=5*(x-3)+27

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Solution for 3*(2x-5)+4x=5*(x-3)+27 equation: 



3*(2x-5)+4x=5*(x-3)+27

We move all terms to the left:

3*(2x-5)+4x-(5*(x-3)+27)=0

We add all the numbers together, and all the variables

4x+3*(2x-5)-(5*(x-3)+27)=0

We multiply parentheses

4x+6x-(5*(x-3)+27)-15=0



We calculate terms in parentheses: -(5*(x-3)+27), so:

5*(x-3)+27

We multiply parentheses

5x-15+27

We add all the numbers together, and all the variables

5x+12

Back to the equation:

-(5x+12)



We add all the numbers together, and all the variables

10x-(5x+12)-15=0

We get rid of parentheses

10x-5x-12-15=0

We add all the numbers together, and all the variables

5x-27=0

We move all terms containing x to the left, all other terms to the right

5x=27

x=27/5

x=5+2/5

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