3*(2q+5)=6*(7+4q)

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Solution for 3*(2q+5)=6*(7+4q) equation: 



3(2q+5)=6(7+4q)

We move all terms to the left:

3(2q+5)-(6(7+4q))=0

We add all the numbers together, and all the variables

3(2q+5)-(6(4q+7))=0

We multiply parentheses

6q-(6(4q+7))+15=0



We calculate terms in parentheses: -(6(4q+7)), so:

6(4q+7)

We multiply parentheses

24q+42

Back to the equation:

-(24q+42)



We get rid of parentheses

6q-24q-42+15=0

We add all the numbers together, and all the variables

-18q-27=0

We move all terms containing q to the left, all other terms to the right

-18q=27

q=27/-18

q=-1+1/2

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