3(z-9)=2(z+3)

Solution for 3(z-9)=2(z+3) equation:

Simplifying
3(z + -9) = 2(z + 3)

Reorder the terms:
3(-9 + z) = 2(z + 3)
(-9 * 3 + z * 3) = 2(z + 3)
(-27 + 3z) = 2(z + 3)

Reorder the terms:
-27 + 3z = 2(3 + z)
-27 + 3z = (3 * 2 + z * 2)
-27 + 3z = (6 + 2z)

Solving
-27 + 3z = 6 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-27 + 3z + -2z = 6 + 2z + -2z

Combine like terms: 3z + -2z = 1z
-27 + 1z = 6 + 2z + -2z

Combine like terms: 2z + -2z = 0
-27 + 1z = 6 + 0
-27 + 1z = 6

Add '27' to each side of the equation.
-27 + 27 + 1z = 6 + 27

Combine like terms: -27 + 27 = 0
0 + 1z = 6 + 27
1z = 6 + 27

Combine like terms: 6 + 27 = 33
1z = 33

Divide each side by '1'.
z = 33

Simplifying
z = 33