3(z-9)+43=-2(4z+3)

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Solution for 3(z-9)+43=-2(4z+3) equation: 



3(z-9)+43=-2(4z+3)

We move all terms to the left:

3(z-9)+43-(-2(4z+3))=0

We multiply parentheses

3z-(-2(4z+3))-27+43=0



We calculate terms in parentheses: -(-2(4z+3)), so:

-2(4z+3)

We multiply parentheses

-8z-6

Back to the equation:

-(-8z-6)



We add all the numbers together, and all the variables

3z-(-8z-6)+16=0

We get rid of parentheses

3z+8z+6+16=0

We add all the numbers together, and all the variables

11z+22=0

We move all terms containing z to the left, all other terms to the right

11z=-22

z=-22/11

z=-2

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