3(z-5)=7(z-1)

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Solution for 3(z-5)=7(z-1) equation:


Simplifying
3(z + -5) = 7(z + -1)

Reorder the terms:
3(-5 + z) = 7(z + -1)
(-5 * 3 + z * 3) = 7(z + -1)
(-15 + 3z) = 7(z + -1)

Reorder the terms:
-15 + 3z = 7(-1 + z)
-15 + 3z = (-1 * 7 + z * 7)
-15 + 3z = (-7 + 7z)

Solving
-15 + 3z = -7 + 7z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7z' to each side of the equation.
-15 + 3z + -7z = -7 + 7z + -7z

Combine like terms: 3z + -7z = -4z
-15 + -4z = -7 + 7z + -7z

Combine like terms: 7z + -7z = 0
-15 + -4z = -7 + 0
-15 + -4z = -7

Add '15' to each side of the equation.
-15 + 15 + -4z = -7 + 15

Combine like terms: -15 + 15 = 0
0 + -4z = -7 + 15
-4z = -7 + 15

Combine like terms: -7 + 15 = 8
-4z = 8

Divide each side by '-4'.
z = -2

Simplifying
z = -2

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