3(z-4)=7z+2

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Solution for 3(z-4)=7z+2 equation:


Simplifying
3(z + -4) = 7z + 2

Reorder the terms:
3(-4 + z) = 7z + 2
(-4 * 3 + z * 3) = 7z + 2
(-12 + 3z) = 7z + 2

Reorder the terms:
-12 + 3z = 2 + 7z

Solving
-12 + 3z = 2 + 7z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7z' to each side of the equation.
-12 + 3z + -7z = 2 + 7z + -7z

Combine like terms: 3z + -7z = -4z
-12 + -4z = 2 + 7z + -7z

Combine like terms: 7z + -7z = 0
-12 + -4z = 2 + 0
-12 + -4z = 2

Add '12' to each side of the equation.
-12 + 12 + -4z = 2 + 12

Combine like terms: -12 + 12 = 0
0 + -4z = 2 + 12
-4z = 2 + 12

Combine like terms: 2 + 12 = 14
-4z = 14

Divide each side by '-4'.
z = -3.5

Simplifying
z = -3.5

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