3(z-4)=7z+1

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Solution for 3(z-4)=7z+1 equation:



3(z-4)=7z+1
We move all terms to the left:
3(z-4)-(7z+1)=0
We multiply parentheses
3z-(7z+1)-12=0
We get rid of parentheses
3z-7z-1-12=0
We add all the numbers together, and all the variables
-4z-13=0
We move all terms containing z to the left, all other terms to the right
-4z=13
z=13/-4
z=-3+1/4

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