3(z-4)=10z-4(z+5)

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Solution for 3(z-4)=10z-4(z+5) equation: 



3(z-4)=10z-4(z+5)

We move all terms to the left:

3(z-4)-(10z-4(z+5))=0

We multiply parentheses

3z-(10z-4(z+5))-12=0



We calculate terms in parentheses: -(10z-4(z+5)), so:

10z-4(z+5)

We multiply parentheses

10z-4z-20

We add all the numbers together, and all the variables

6z-20

Back to the equation:

-(6z-20)



We get rid of parentheses

3z-6z+20-12=0

We add all the numbers together, and all the variables

-3z+8=0

We move all terms containing z to the left, all other terms to the right

-3z=-8

z=-8/-3

z=2+2/3

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