3(z-4)=-2(z+5)+8

Solution for 3(z-4)=-2(z+5)+8 equation:

3(z-4)=-2(z+5)+8

We move all terms to the left:

3(z-4)-(-2(z+5)+8)=0

We multiply parentheses

3z-(-2(z+5)+8)-12=0


We calculate terms in parentheses: -(-2(z+5)+8), so:

-2(z+5)+8

We multiply parentheses

-2z-10+8

We add all the numbers together, and all the variables

-2z-2

Back to the equation:

-(-2z-2)


We get rid of parentheses

3z+2z+2-12=0

We add all the numbers together, and all the variables

5z-10=0

We move all terms containing z to the left, all other terms to the right

5z=10

z=10/5

z=2