3(z-4)-6(2z-3)=12-7z

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Solution for 3(z-4)-6(2z-3)=12-7z equation: 



3(z-4)-6(2z-3)=12-7z

We move all terms to the left:

3(z-4)-6(2z-3)-(12-7z)=0

We add all the numbers together, and all the variables

3(z-4)-6(2z-3)-(-7z+12)=0

We multiply parentheses

3z-12z-(-7z+12)-12+18=0

We get rid of parentheses

3z-12z+7z-12-12+18=0

We add all the numbers together, and all the variables

-2z-6=0

We move all terms containing z to the left, all other terms to the right

-2z=6

z=6/-2

z=-3

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