3(z-3)=7z+2

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Solution for 3(z-3)=7z+2 equation: 



3(z-3)=7z+2

We move all terms to the left:

3(z-3)-(7z+2)=0

We multiply parentheses

3z-(7z+2)-9=0

We get rid of parentheses

3z-7z-2-9=0

We add all the numbers together, and all the variables

-4z-11=0

We move all terms containing z to the left, all other terms to the right

-4z=11

z=11/-4

z=-2+3/4

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