3(z-3)=7z+1

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Solution for 3(z-3)=7z+1 equation: 



3(z-3)=7z+1

We move all terms to the left:

3(z-3)-(7z+1)=0

We multiply parentheses

3z-(7z+1)-9=0

We get rid of parentheses

3z-7z-1-9=0

We add all the numbers together, and all the variables

-4z-10=0

We move all terms containing z to the left, all other terms to the right

-4z=10

z=10/-4

z=-2+1/2

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