3(z-3)=39-3(z-2)

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Solution for 3(z-3)=39-3(z-2) equation:


Simplifying
3(z + -3) = 39 + -3(z + -2)

Reorder the terms:
3(-3 + z) = 39 + -3(z + -2)
(-3 * 3 + z * 3) = 39 + -3(z + -2)
(-9 + 3z) = 39 + -3(z + -2)

Reorder the terms:
-9 + 3z = 39 + -3(-2 + z)
-9 + 3z = 39 + (-2 * -3 + z * -3)
-9 + 3z = 39 + (6 + -3z)

Combine like terms: 39 + 6 = 45
-9 + 3z = 45 + -3z

Solving
-9 + 3z = 45 + -3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '3z' to each side of the equation.
-9 + 3z + 3z = 45 + -3z + 3z

Combine like terms: 3z + 3z = 6z
-9 + 6z = 45 + -3z + 3z

Combine like terms: -3z + 3z = 0
-9 + 6z = 45 + 0
-9 + 6z = 45

Add '9' to each side of the equation.
-9 + 9 + 6z = 45 + 9

Combine like terms: -9 + 9 = 0
0 + 6z = 45 + 9
6z = 45 + 9

Combine like terms: 45 + 9 = 54
6z = 54

Divide each side by '6'.
z = 9

Simplifying
z = 9

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