3(z-23)+3(z-4)=33

Solution for 3(z-23)+3(z-4)=33 equation:

Simplifying
3(z + -23) + 3(z + -4) = 33

Reorder the terms:
3(-23 + z) + 3(z + -4) = 33
(-23 * 3 + z * 3) + 3(z + -4) = 33
(-69 + 3z) + 3(z + -4) = 33

Reorder the terms:
-69 + 3z + 3(-4 + z) = 33
-69 + 3z + (-4 * 3 + z * 3) = 33
-69 + 3z + (-12 + 3z) = 33

Reorder the terms:
-69 + -12 + 3z + 3z = 33

Combine like terms: -69 + -12 = -81
-81 + 3z + 3z = 33

Combine like terms: 3z + 3z = 6z
-81 + 6z = 33

Solving
-81 + 6z = 33

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '81' to each side of the equation.
-81 + 81 + 6z = 33 + 81

Combine like terms: -81 + 81 = 0
0 + 6z = 33 + 81
6z = 33 + 81

Combine like terms: 33 + 81 = 114
6z = 114

Divide each side by '6'.
z = 19

Simplifying
z = 19