3(z-22)+2(z-4)=6

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Solution for 3(z-22)+2(z-4)=6 equation:


Simplifying
3(z + -22) + 2(z + -4) = 6

Reorder the terms:
3(-22 + z) + 2(z + -4) = 6
(-22 * 3 + z * 3) + 2(z + -4) = 6
(-66 + 3z) + 2(z + -4) = 6

Reorder the terms:
-66 + 3z + 2(-4 + z) = 6
-66 + 3z + (-4 * 2 + z * 2) = 6
-66 + 3z + (-8 + 2z) = 6

Reorder the terms:
-66 + -8 + 3z + 2z = 6

Combine like terms: -66 + -8 = -74
-74 + 3z + 2z = 6

Combine like terms: 3z + 2z = 5z
-74 + 5z = 6

Solving
-74 + 5z = 6

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '74' to each side of the equation.
-74 + 74 + 5z = 6 + 74

Combine like terms: -74 + 74 = 0
0 + 5z = 6 + 74
5z = 6 + 74

Combine like terms: 6 + 74 = 80
5z = 80

Divide each side by '5'.
z = 16

Simplifying
z = 16

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