3(z-22)+2(z-2)=20

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Solution for 3(z-22)+2(z-2)=20 equation: 


Simplifying
3(z + -22) + 2(z + -2) = 20

Reorder the terms:
3(-22 + z) + 2(z + -2) = 20
(-22 * 3 + z * 3) + 2(z + -2) = 20
(-66 + 3z) + 2(z + -2) = 20

Reorder the terms:
-66 + 3z + 2(-2 + z) = 20
-66 + 3z + (-2 * 2 + z * 2) = 20
-66 + 3z + (-4 + 2z) = 20

Reorder the terms:
-66 + -4 + 3z + 2z = 20

Combine like terms: -66 + -4 = -70
-70 + 3z + 2z = 20

Combine like terms: 3z + 2z = 5z
-70 + 5z = 20

Solving
-70 + 5z = 20

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '70' to each side of the equation.
-70 + 70 + 5z = 20 + 70

Combine like terms: -70 + 70 = 0
0 + 5z = 20 + 70
5z = 20 + 70

Combine like terms: 20 + 70 = 90
5z = 90

Divide each side by '5'.
z = 18

Simplifying
z = 18

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