3(z-21)+3(z-4)=27

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Solution for 3(z-21)+3(z-4)=27 equation:


Simplifying
3(z + -21) + 3(z + -4) = 27

Reorder the terms:
3(-21 + z) + 3(z + -4) = 27
(-21 * 3 + z * 3) + 3(z + -4) = 27
(-63 + 3z) + 3(z + -4) = 27

Reorder the terms:
-63 + 3z + 3(-4 + z) = 27
-63 + 3z + (-4 * 3 + z * 3) = 27
-63 + 3z + (-12 + 3z) = 27

Reorder the terms:
-63 + -12 + 3z + 3z = 27

Combine like terms: -63 + -12 = -75
-75 + 3z + 3z = 27

Combine like terms: 3z + 3z = 6z
-75 + 6z = 27

Solving
-75 + 6z = 27

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '75' to each side of the equation.
-75 + 75 + 6z = 27 + 75

Combine like terms: -75 + 75 = 0
0 + 6z = 27 + 75
6z = 27 + 75

Combine like terms: 27 + 75 = 102
6z = 102

Divide each side by '6'.
z = 17

Simplifying
z = 17

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