3(z-2)=5z+1=

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Solution for 3(z-2)=5z+1= equation: 



3(z-2)=5z+1=

We move all terms to the left:

3(z-2)-(5z+1)=0

We multiply parentheses

3z-(5z+1)-6=0

We get rid of parentheses

3z-5z-1-6=0

We add all the numbers together, and all the variables

-2z-7=0

We move all terms containing z to the left, all other terms to the right

-2z=7

z=7/-2

z=-3+1/2

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