3(z-2)=4(z-3)

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Solution for 3(z-2)=4(z-3) equation: 



3(z-2)=4(z-3)

We move all terms to the left:

3(z-2)-(4(z-3))=0

We multiply parentheses

3z-(4(z-3))-6=0



We calculate terms in parentheses: -(4(z-3)), so:

4(z-3)

We multiply parentheses

4z-12

Back to the equation:

-(4z-12)



We get rid of parentheses

3z-4z+12-6=0

We add all the numbers together, and all the variables

-1z+6=0

We move all terms containing z to the left, all other terms to the right

-z=-6

z=-6/-1

z=+6

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