3(z-2)=2(z+1)

Solution for 3(z-2)=2(z+1) equation:

Simplifying
3(z + -2) = 2(z + 1)

Reorder the terms:
3(-2 + z) = 2(z + 1)
(-2 * 3 + z * 3) = 2(z + 1)
(-6 + 3z) = 2(z + 1)

Reorder the terms:
-6 + 3z = 2(1 + z)
-6 + 3z = (1 * 2 + z * 2)
-6 + 3z = (2 + 2z)

Solving
-6 + 3z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-6 + 3z + -2z = 2 + 2z + -2z

Combine like terms: 3z + -2z = 1z
-6 + 1z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-6 + 1z = 2 + 0
-6 + 1z = 2

Add '6' to each side of the equation.
-6 + 6 + 1z = 2 + 6

Combine like terms: -6 + 6 = 0
0 + 1z = 2 + 6
1z = 2 + 6

Combine like terms: 2 + 6 = 8
1z = 8

Divide each side by '1'.
z = 8

Simplifying
z = 8