3(z-2)=10+2z

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Solution for 3(z-2)=10+2z equation:



3(z-2)=10+2z
We move all terms to the left:
3(z-2)-(10+2z)=0
We add all the numbers together, and all the variables
3(z-2)-(2z+10)=0
We multiply parentheses
3z-(2z+10)-6=0
We get rid of parentheses
3z-2z-10-6=0
We add all the numbers together, and all the variables
z-16=0
We move all terms containing z to the left, all other terms to the right
z=16

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