3(z-2)=(2z-1)

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Solution for 3(z-2)=(2z-1) equation: 



3(z-2)=(2z-1)

We move all terms to the left:

3(z-2)-((2z-1))=0

We multiply parentheses

3z-((2z-1))-6=0



We calculate terms in parentheses: -((2z-1)), so:

(2z-1)

We get rid of parentheses

2z-1

Back to the equation:

-(2z-1)



We get rid of parentheses

3z-2z+1-6=0

We add all the numbers together, and all the variables

z-5=0

We move all terms containing z to the left, all other terms to the right

z=5

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