3(z-2)+6=5(z-4)

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Solution for 3(z-2)+6=5(z-4) equation:


Simplifying
3(z + -2) + 6 = 5(z + -4)

Reorder the terms:
3(-2 + z) + 6 = 5(z + -4)
(-2 * 3 + z * 3) + 6 = 5(z + -4)
(-6 + 3z) + 6 = 5(z + -4)

Reorder the terms:
-6 + 6 + 3z = 5(z + -4)

Combine like terms: -6 + 6 = 0
0 + 3z = 5(z + -4)
3z = 5(z + -4)

Reorder the terms:
3z = 5(-4 + z)
3z = (-4 * 5 + z * 5)
3z = (-20 + 5z)

Solving
3z = -20 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
3z + -5z = -20 + 5z + -5z

Combine like terms: 3z + -5z = -2z
-2z = -20 + 5z + -5z

Combine like terms: 5z + -5z = 0
-2z = -20 + 0
-2z = -20

Divide each side by '-2'.
z = 10

Simplifying
z = 10

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