3(z-12)+6=12

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Solution for 3(z-12)+6=12 equation: 



3(z-12)+6=12

We move all terms to the left:

3(z-12)+6-(12)=0

We add all the numbers together, and all the variables

3(z-12)-6=0

We multiply parentheses

3z-36-6=0

We add all the numbers together, and all the variables

3z-42=0

We move all terms containing z to the left, all other terms to the right

3z=42

z=42/3

z=14

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