3(z-1)-z-7=2z+6

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Solution for 3(z-1)-z-7=2z+6 equation: 


Simplifying
3(z + -1) + -1z + -7 = 2z + 6

Reorder the terms:
3(-1 + z) + -1z + -7 = 2z + 6
(-1 * 3 + z * 3) + -1z + -7 = 2z + 6
(-3 + 3z) + -1z + -7 = 2z + 6

Reorder the terms:
-3 + -7 + 3z + -1z = 2z + 6

Combine like terms: -3 + -7 = -10
-10 + 3z + -1z = 2z + 6

Combine like terms: 3z + -1z = 2z
-10 + 2z = 2z + 6

Reorder the terms:
-10 + 2z = 6 + 2z

Add '-2z' to each side of the equation.
-10 + 2z + -2z = 6 + 2z + -2z

Combine like terms: 2z + -2z = 0
-10 + 0 = 6 + 2z + -2z
-10 = 6 + 2z + -2z

Combine like terms: 2z + -2z = 0
-10 = 6 + 0
-10 = 6

Solving
-10 = 6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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