3(z-1)-4(5-2)=2(6+z)

Solution for 3(z-1)-4(5-2)=2(6+z) equation:

Simplifying
3(z + -1) + -4(5 + -2) = 2(6 + z)

Reorder the terms:
3(-1 + z) + -4(5 + -2) = 2(6 + z)
(-1 * 3 + z * 3) + -4(5 + -2) = 2(6 + z)
(-3 + 3z) + -4(5 + -2) = 2(6 + z)

Combine like terms: 5 + -2 = 3
-3 + 3z + -4(3) = 2(6 + z)

Multiply -4 * 3
-3 + 3z + -12 = 2(6 + z)

Reorder the terms:
-3 + -12 + 3z = 2(6 + z)

Combine like terms: -3 + -12 = -15
-15 + 3z = 2(6 + z)
-15 + 3z = (6 * 2 + z * 2)
-15 + 3z = (12 + 2z)

Solving
-15 + 3z = 12 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-15 + 3z + -2z = 12 + 2z + -2z

Combine like terms: 3z + -2z = 1z
-15 + 1z = 12 + 2z + -2z

Combine like terms: 2z + -2z = 0
-15 + 1z = 12 + 0
-15 + 1z = 12

Add '15' to each side of the equation.
-15 + 15 + 1z = 12 + 15

Combine like terms: -15 + 15 = 0
0 + 1z = 12 + 15
1z = 12 + 15

Combine like terms: 12 + 15 = 27
1z = 27

Divide each side by '1'.
z = 27

Simplifying
z = 27