3(z-(4z+9)+6)=4(z+1)

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Solution for 3(z-(4z+9)+6)=4(z+1) equation:


Simplifying
3(z + -1(4z + 9) + 6) = 4(z + 1)

Reorder the terms:
3(z + -1(9 + 4z) + 6) = 4(z + 1)
3(z + (9 * -1 + 4z * -1) + 6) = 4(z + 1)
3(z + (-9 + -4z) + 6) = 4(z + 1)

Reorder the terms:
3(-9 + 6 + z + -4z) = 4(z + 1)

Combine like terms: -9 + 6 = -3
3(-3 + z + -4z) = 4(z + 1)

Combine like terms: z + -4z = -3z
3(-3 + -3z) = 4(z + 1)
(-3 * 3 + -3z * 3) = 4(z + 1)
(-9 + -9z) = 4(z + 1)

Reorder the terms:
-9 + -9z = 4(1 + z)
-9 + -9z = (1 * 4 + z * 4)
-9 + -9z = (4 + 4z)

Solving
-9 + -9z = 4 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-9 + -9z + -4z = 4 + 4z + -4z

Combine like terms: -9z + -4z = -13z
-9 + -13z = 4 + 4z + -4z

Combine like terms: 4z + -4z = 0
-9 + -13z = 4 + 0
-9 + -13z = 4

Add '9' to each side of the equation.
-9 + 9 + -13z = 4 + 9

Combine like terms: -9 + 9 = 0
0 + -13z = 4 + 9
-13z = 4 + 9

Combine like terms: 4 + 9 = 13
-13z = 13

Divide each side by '-13'.
z = -1

Simplifying
z = -1

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