3(z+5)=4(2z-5)

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Solution for 3(z+5)=4(2z-5) equation: 



3(z+5)=4(2z-5)

We move all terms to the left:

3(z+5)-(4(2z-5))=0

We multiply parentheses

3z-(4(2z-5))+15=0



We calculate terms in parentheses: -(4(2z-5)), so:

4(2z-5)

We multiply parentheses

8z-20

Back to the equation:

-(8z-20)



We get rid of parentheses

3z-8z+20+15=0

We add all the numbers together, and all the variables

-5z+35=0

We move all terms containing z to the left, all other terms to the right

-5z=-35

z=-35/-5

z=+7

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