3(z+4)=2(z-3)+z

Solution for 3(z+4)=2(z-3)+z equation:

Simplifying
3(z + 4) = 2(z + -3) + z

Reorder the terms:
3(4 + z) = 2(z + -3) + z
(4 * 3 + z * 3) = 2(z + -3) + z
(12 + 3z) = 2(z + -3) + z

Reorder the terms:
12 + 3z = 2(-3 + z) + z
12 + 3z = (-3 * 2 + z * 2) + z
12 + 3z = (-6 + 2z) + z

Combine like terms: 2z + z = 3z
12 + 3z = -6 + 3z

Add '-3z' to each side of the equation.
12 + 3z + -3z = -6 + 3z + -3z

Combine like terms: 3z + -3z = 0
12 + 0 = -6 + 3z + -3z
12 = -6 + 3z + -3z

Combine like terms: 3z + -3z = 0
12 = -6 + 0
12 = -6

Solving
12 = -6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.