3(z+3)=2(z-6)+z

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Solution for 3(z+3)=2(z-6)+z equation: 


Simplifying
3(z + 3) = 2(z + -6) + z

Reorder the terms:
3(3 + z) = 2(z + -6) + z
(3 * 3 + z * 3) = 2(z + -6) + z
(9 + 3z) = 2(z + -6) + z

Reorder the terms:
9 + 3z = 2(-6 + z) + z
9 + 3z = (-6 * 2 + z * 2) + z
9 + 3z = (-12 + 2z) + z

Combine like terms: 2z + z = 3z
9 + 3z = -12 + 3z

Add '-3z' to each side of the equation.
9 + 3z + -3z = -12 + 3z + -3z

Combine like terms: 3z + -3z = 0
9 + 0 = -12 + 3z + -3z
9 = -12 + 3z + -3z

Combine like terms: 3z + -3z = 0
9 = -12 + 0
9 = -12

Solving
9 = -12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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