3(z+3)+2=20

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Solution for 3(z+3)+2=20 equation: 



3(z+3)+2=20

We move all terms to the left:

3(z+3)+2-(20)=0

We add all the numbers together, and all the variables

3(z+3)-18=0

We multiply parentheses

3z+9-18=0

We add all the numbers together, and all the variables

3z-9=0

We move all terms containing z to the left, all other terms to the right

3z=9

z=9/3

z=3

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