3(z+2)=52+6

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Solution for 3(z+2)=52+6 equation:



3(z+2)=52+6
We move all terms to the left:
3(z+2)-(52+6)=0
We add all the numbers together, and all the variables
3(z+2)-58=0
We multiply parentheses
3z+6-58=0
We add all the numbers together, and all the variables
3z-52=0
We move all terms containing z to the left, all other terms to the right
3z=52
z=52/3
z=17+1/3

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